(z-2i)(z^2-2i)=0

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Solution for (z-2i)(z^2-2i)=0 equation:


Simplifying
(z + -2i)(z2 + -2i) = 0

Reorder the terms:
(-2i + z)(z2 + -2i) = 0

Reorder the terms:
(-2i + z)(-2i + z2) = 0

Multiply (-2i + z) * (-2i + z2)
(-2i * (-2i + z2) + z(-2i + z2)) = 0
((-2i * -2i + z2 * -2i) + z(-2i + z2)) = 0

Reorder the terms:
((-2iz2 + 4i2) + z(-2i + z2)) = 0
((-2iz2 + 4i2) + z(-2i + z2)) = 0
(-2iz2 + 4i2 + (-2i * z + z2 * z)) = 0
(-2iz2 + 4i2 + (-2iz + z3)) = 0

Reorder the terms:
(-2iz + -2iz2 + 4i2 + z3) = 0
(-2iz + -2iz2 + 4i2 + z3) = 0

Solving
-2iz + -2iz2 + 4i2 + z3 = 0

Solving for variable 'i'.

The solution to this equation could not be determined.

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